What is the equation of a line that passes through the point (8, -4) and is parrallel to the line 6x + 2y = 9

Question 1

Accepted Answer

at home andrea has 1 2/3 kilograms of ricestep-by-step explanation:

Question 2

What is the slope of the line that passes through the points (8,-4) and (6,2)

Accepted Answer

M= slopeM= -3Step-by-step explanation: M= the change in y over the change in x so you do -4-2 over 8-6 which would give you -6 over 2 which is simplified to give you the answer which is -3

Question 3

What is the slope of the line that passes through these points (8,-4) and (6,2)

Accepted Answer

The slope of the line is -3.To find this, all you need to do is use the formula y2 - y1 / x2 - x1. This is referred to as rise/run and all you do is plug in the two point for the x and y values.

Question 4

Write the equation of a line that is perpendicular to y=-1 and that passes through the point (8,-4)

Accepted Answer

x=8Step-by-step explanation:y=-1 is a horizontal line, meaning that the line perpendicular to it must have a undefined slope (x=a). since the x-coordinate of the point we want to pass through is 8, the line must be x = 8

What is the equation of a line that passes through the point (8, -4) and is parrallel to the line 6x + 2y = 9

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